9y^2+0,27y=0

Solution for 9y^2+0,27y=0 equation:

9y^2+0.27y=0

a = 9; b = 0.27; c = 0;
Δ = b2-4ac
Δ = 0.272-4·9·0
Δ = 0.0729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.27)-\sqrt{0.0729}}{2*9}=\frac{-0.27-\sqrt{0.0729}}{18}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.27)+\sqrt{0.0729}}{2*9}=\frac{-0.27+\sqrt{0.0729}}{18}
$